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Questions in mathematics
[Free] y = 65x Which could NOT be a point on this table? (2,130) (8,455) (1,65) (11,715)
[Free] Divide: [tex]25 x y^4+60 x y^3[/tex] by [tex]5xy[/tex] A. [tex]5 x y^3+12 x y^2[/tex] B. [tex]5 y^2+12[/tex] C. [tex]5 x y+12 y[/tex] D. [tex]5 y^3+12 y^2[/tex]
[Free] By the end of year 8, would Demarco and Tanya have to pay a final payout of? A. $120,887 B. $130,900 C. $143,152 D. $154,768
[Free] Is this equation an identity? [tex]11.21+11.9 k=11.9 k+11.21[/tex] Answer: yes no
[Free] Simplify: $b+7+b-2$ A. 7 B. $-7+9 b$ C. $-6 b$ D. $2 b+5$
[Free] What are the $x$- and $y$-coordinates of point P on the directed line segment from K to J such that P is $\frac{3}{5}$ the length of the line segment from K to J? $x=\left(\frac{m}{m+n}\right)\left(x_2-x_1\right)+x_1$ $v=\left(\frac{m}{m+n}\right)\left(v_2-v_1\right)+v_1$ A. $(40,96)$ B. $(85,105)$ C. $(80,104)$ D. $(96,72)$
[Free] Simplify $(5 x^4 y^4 z)^3(x^4 y)^4$
[Free] Find the simplified product: [tex]$\sqrt{2 x^3} \cdot \sqrt{18 x^5}$[/tex]
[Free] A student stated that there are two solutions to the equation [tex]$\sqrt{ }(3 x+7)=x-1$[/tex] They are [tex]$x=-1$[/tex] and [tex]$x=6$[/tex]. Do you agree with the student? Explain why or why not. A. I do not agree with the student because there is no real solution. B. Checking the solutions in the original equation verifies [tex]$x=6$[/tex]; however, [tex]$x=-1$[/tex] is extraneous. C. Checking the solutions in the original equation shows that 6 is an extraneous solution. D. I agree with the student because both [tex]$x=-1$[/tex] and [tex]$x=6$[/tex] satisfy the original equation.
[Free] What is the simplified form of the following expression? Assume [tex]$x \neq 0$[/tex]. [tex]$\sqrt[5]{\frac{10 x}{3 x^3}}$[/tex]
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