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Questions in mathematics
[Free] A mobile carrier in a city has 576 subscribers. If the number of subscribers increases by 30% every year, how many subscribers will there be after 3 years? [tex]Future Amount =I(1+r)^t[/tex] Round your answer to the nearest whole number.
[Free] Find the range of values: (a) [tex]\frac{x-3}{x+3}\ \textgreater \ 0[/tex] (c) [tex]\frac{2 x+1}{x-3}\ \textgreater \ 0[/tex]
[Free] How many solutions does this equation have? [tex]12.9 f=-5.3 f+18.2 f[/tex] * no solution * one solution * infinitely many solutions
[Free] Mary's yard is a mess. She needs to hire someone to prune her trees and shrubs. A landscaping service she calls quotes her a price of $[tex]$15$[/tex] consultation fee plus $[tex]$8$[/tex] an hour for the actual work. Mary's neighbor has offered to help her out. She doesn't charge a consultation fee, but does charge $[tex]$10$[/tex] an hour for her work. Write two equations, one that describes the landscaping service charge and one that describes your neighbor's charge. Let [tex]$C$[/tex] equal the charge as a function of [tex]$h$[/tex], the number of hours worked. A. [tex]$C=15+10 h$[/tex] [tex]$C=8 h$[/tex] B. [tex]$C=10 h+8 h$[/tex] [tex]$C=15$[/tex] C. [tex]$C=15+8 h$[/tex] [tex]$C=10 h$[/tex] D. [tex]$C=18 h$[/tex] [tex]$C=15$[/tex]
[Free] Listen $7+7+(-1)=$ A) 10 B) 7 C) 16 D) 13
[Free] What are the coordinates of the vertex of the parabola $y=x^2-2 x-1$? A. $(-1,2)$ B. $(1,2)$ C. $(-1,-2)$ D. $(1,-2)
[Free] Jeremy spent \frac{1}{5} of his money and \frac{1}{8} of the remaining money on some drinks. He was then left with $21. How much money did he have at first?
[Free] 5. The cost of a computer is ₹75750. Find the cost of 110 such computers. 6. There are 240 pages in a book. Find the total number of pages in such 3268 books.
[Free] What is the slope of the line represented by the equation $y=-\frac{2}{3}-5 x$? A. -5 B. $-\frac{2}{3}$ C. $\frac{2}{3}$ D. 5
[Free] $(2 p^2+7 p-3)(8 p-4)$ A) $40 p^3+24 p^2+32 p+48$ B) $15 p^3+16 p^2-24 p-64$ C) $16 p^3+48 p^2-52 p+12$ D) $12 p^3+34 p^2-18 p-16$ E) $40 p^3+6 p^2+4 p-2$
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