Using the information in the table to the right, calculate the average atomic mass of strontium. Report to two decimal places.
| Isotope | Mass (amu) | Abundance |
|---|---|---|
| Sr-84 | 83.913428 | 0.56 % |
| Sr-86 | 85.909273 | 9.86 % |
| Sr-87 | 86.908902 | 7.00 % |
| Sr-88 | 87.905625 | 82.58 % |
Answer (3)
He can make 12 bows made out of ribbon. You do this by multiplying the dinominator with the yards of ribbon
I think Deon can make 12 bows.
Deon can make 12 bows with 4 yards of ribbon since each bow requires 3 1 yard. To find this, we divide 4 yards by 3 1 yard per bow, which is equivalent to multiplying by 3, resulting in 12 bows. Therefore, he has enough ribbon for 12 bows.
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