Let's try a problem. You heat 2.0 kg of water to make pasta. The temperature of the water before you heat it is [tex]$40^{\circ} C$[/tex]. The temperature of the water after you heat it is [tex]$100^{\circ} C$[/tex]. How much heat was transferred to the water? (The specific heat of water is [tex]$4,184 J / kg \cdot{ }^{\circ} C$[/tex]). Step 1: Write the equation. heat = specific heat [tex]$\times$[/tex] mass [tex]$\times$[/tex] change in temperature Step 2: Place values into the equation, and solve. [tex]$\text { heat }=4,184 J / kg \cdot{ }^{\circ} C \times 2.0 kg \times\left(100^{\circ} C-40^{\circ} C\right)=502,080 J . $[/tex] The heat transferred is [tex]$502,080 J$[/tex]. Calculate Use the data in the figure to determine the energy needed to warm the water in the cup.
Answer (2)
They are the commutative, associative, multiplicative identity and distributive properties.
Commutative property: For example 6 * 7 = 7 * 6;
Associative Property: For example (7 * 8) * 9 = 7 * (8 * 9);
Multiplicative Identity Property: For example 6 * 1 = 6 or, 1 * 6 = 6;
Distributive property: For example 6 * ( 7 + 8) = 6 * 7 + 6 * 8 or, ( 7 + 8) * 6 = 7 * 6 + 8 * 6.
Multiplication has key properties including the commutative, associative, multiplicative identity, and distributive properties. By using a number line from 0 to 27, we illustrated examples with the numbers 6, 7, 8, and 9 to demonstrate these properties. This approach helps learners see how multiplication operates systematically and consistently in mathematics.
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