(4-3i)(2+i)=8+4i-6i-3i^2=8-2i+3=11-2i recall that i*i= -1
11-2i ;
The product of the complex numbers 4 − 3 i and 2 + i is 11 − 2 i . This is found by using the distributive property to multiply the two numbers, simplifying the expression, and recalling that i 2 = − 1 . Hence, the final result is in the form a + bi .
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