17. 2071 Set D Q.No. 10a Ultraviolet light of wavelength [tex]$3.6 \times 10^{-7} m$[/tex] is made to fall on a smooth surface of potassium. Determine maximum energy of emitted photo electrons and stopping potential.
[4]
Ans: [tex]$1.5 eV , 1.5 V$[/tex]
18. 2070 Supp. Set [tex]$B$[/tex] Q.No. 10a Electrons with maximum kinetic energy of 3 eV are ejected from a metal surface by ultra-violet radiation of wavelength [tex]$1.5 \times 10^{-7} m$[/tex]. Determine work function, threshold wavelength and the stopping potential for the metal (Planck's constant, [tex]$h =6.62 \times 10^{-34} Js$[/tex] )
[4]
Ans: [tex]$5.275 eV ., 2.35 \times 10^{-7} m, 3 V$[/tex]
19. 2070 Set C Q.No. 10b The photoelectric threshold wavelength of a tungsten surface is 272 nm . Calculate the maximum velocity of the electrons ejected from this tungsten surface by ultraviolet radiation of frequency [tex]$1.45 \times 10^{15} Hz$[/tex].
([tex]$h=6.62 \times 10^{-34} Js, c=3 \times 10^8 m / s, me=9.1 \times 10^{-31} kg$[/tex])
Ans: [tex]$7.1 \times 10^5 m / sec$[/tex]
Answer (3)
**Answer: -1/2 or 1/2 ** ;
The slope of the line represented by the equation y = x/6 - 1/2 is 1/6.
Correct option is C.
Given that an equation y = x/6 - 1/2, we need to find the slope of the line represented by this equation,
The equation you've provided is in the form of a** linear equation**, y = mx + b, where "m" represents the slope of the line and "b" represents the y-intercept.
In your equation, y = x/6 - 1/2, the coefficient of "x" is 1/6, which corresponds to the slope of the line.
So, the slope (m) is 1/6.
Hence, the slope of the line is 1/6.
Correct option is C.
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The slope of the line given by the equation y = 6 1 x − 2 1 is 6 1 . This means that for every 6 units you move horizontally to the right, the line rises by 1 unit vertically.
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