2r + 3s= 9 <=> -6r -9s = -27; 3r + 2s= 12 <=> 6r + 4s = 24; => 0 r -5 s = -3 => s = 3/5;
2 r + 3 (3/5) = 9<=> 10 r + 9 = 45 <=> 10 r = 36 => r = 18/5;
(18/5,3/5) ;
Using elimination, we found that r = 5 18 and s = 5 3 . We eliminated one variable by first modifying the equations and then substituted back to find the values. This process illustrates how to solve a system of equations step-by-step using the elimination method.
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