Two people quit work and begin college at the same time. Their salary and education information is given in the table below.
\begin{tabular}{|l|l|l|l|l|}
\hline & Salary prior to school & Years attending college & Total cost of college & Salary upon graduating \\
\hline Person A & $18,000 & 3 & $45000 & $33,000 \\
\hline Person B & $27,000 & 4 & $30,000 & $37,000 \\
\hline & & & & \\
\hline
\end{tabular}
Choose the true statement.
a. Person A recovers their investment in a shorter amount of time.
b. Person B recovers their investment in a shorter amount of time.
c. They recover their investments in the same amount of time.
d. There is too little information to compare the time to recover their investments.
Answer (3)
Let's name the digit:
x- ones digit y - tens digit
we know that x=y-2.
Now, y can be 6,7,8,9 (the number is between 60 and 100 (so depending on your understanding of "between", 0 is also possible. but then the number would have to have -2 as its ones digit, so in any case, it's not possible).
So the possibilities with x=y-2:
64 75 86 97 Out of those 64 and 86 are even, so they can't be prime. 75 has 5 in its ones number: it's divisible by 5.
so the correct answer is 97.
Find the number in where it is between 60 and 100.
Its ones digit is 2 less than its tens digits. And it is a prime number.
=> thus the digit is 2 digit since it has ones and tens place value.
Let’s assign a variable to use. Let a be the value of ones and b the value of tens
ones = A – 2
tens = y
So let’s find the number between 60 to 100 that the value of ones is 2 less than the value of tens
=> 64
=> 75
=> 86
=> 97
Now, we have possible answers. However, prime numbers are not divisible and is not even numbers.
So the answer is 97.
The number you are looking for is 97. It meets the criteria of being between 60 and 100, has a ones digit that is two less than the tens digit, and is a prime number. 97 is indeed a prime number with no divisors other than 1 and itself.
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