The table gives the data that is needed to calculate the average atomic mass of element B.
| Isotope | Atomic mass (amu) | Relative abundance (%) |
|---|---|---|
| B-10 | 10.01 | 19.91 |
| B-11 | 11.01 | 80.09 |
Based on these data, what is the average atomic mass of element B?
A. 10.5
B. 10.01
C. 11.01
D. 10.81
Answer (3)
It's gonna be a long problem: Remember PEMDAS 3n-5=8(6+5n) 3n-5= 48 + 40n Distribute 8 into parenthesis 3n-3n-5=48+40n-3n Put variable on one side. -5-48=48-48+37n Isolate the variable -43/37=37n/37 Isolate variable more -1.162=n Simplify The answer is repeating; that is a shortened version.
t's gonna be a long problem: Remember PEMDAS
3n-5=8(6+5n)
3n-5= 48 + 40n Distribute 8 into parenthesis
3n-3n-5=48+40n-3n Put variable on one side.
-5-48=48-48+37n Isolate the variable
-43/37=37n/37 Isolate variable more
-1.162=n Simplify
The answer is repeating; that is a shortened version.
To solve the equation 3 n − 5 = − 8 ( 6 + 5 n ) , we first distribute − 8 , then isolate n by moving terms. The final solution for n is − 1 .
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