20) 13.74 L of hydrogen gas at [tex]$30.0^{\circ} C$[/tex] and 801 torr and 6.55 L of oxygen gas at [tex]$25^{\circ} C$[/tex] and 801 torr are drawn into a cylinder where the following reaction takes place.
[tex]$2 H_{2(g)}+O_{2(g)} \rightarrow 2 H_2 O_{(g)}$[/tex]
a. How many grams of water could be produced in this reaction?
b. What is the limiting reactant?
c. If 8.7 g of water are produced, what is the percent yield?

From largest to smallest:
3 hundreds (300) , 6 tens (60) , 8 ones (8)
hope this helped :)

Answered by supervishnu04 | 2024-06-10

3 hundreds>6 tens>8ones Because: 3 hundreds=300 6 tens=60 8 ones=8 Then 300>60>8 Which is... 3 hundreds>6 tens>8 ones

Answered by mini | 2024-06-10

The numbers from largest to smallest are 3 hundreds, 6 tens, and 8 ones, represented as 300, 60, and 8 respectively. Thus, the order is 300 > 60 > 8. Therefore, we can express it as 3 hundreds > 6 tens > 8 ones.
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Answered by mini | 2024-10-01