120= 2(w+20) + 2w 120= 2w+40+2w 120= 40+4w 80=4w w=20 Length: w+20 20+20 40 Width: 20 So the dimensions are: Length is 40 Width is 20
**Rectangle **with **perimeter **120m has its length and breadth 40 m and 20 m respectively.
**Dimension **of rectangle : 40 × 20
Given, that **perimeter **of rectangle is 120 m.
Now, perimeter of **rectangle **is given by:
P = 2(l+b)
l = Length of rectangle .
b = Breadth of rectangle.
Let the breadth of **rectangle **be 'x' m.
Then length will be (x+20) m.
Substitute the values in the **perimeter **formula,
P = 2 ( l + b ) 120 = 2 ( x + 20 + x ) 120 = 2 ( 2 x + 20 ) 60 = 2 x + 20 x = 20
Thus the **breadth **of rectangle is 20 m.
Length of rectangle is 20 m more than the breadth.
Length = 20 + 20
**Length **= 40 m.
Therefore the **dimensions **of rectangle is 40 × 20.
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The dimensions of the rectangle are 40 meters in length and 20 meters in width. This is derived from the perimeter formula and the relationship between length and width. The width is 20 meters and the length is 20 meters more than that, making it 40 meters.
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