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In Business / College | 2025-08-20

A thank-you message combined with confirmation of purchase is known as a(n):
A. favorable response
B. good-news message
C. order acknowledgment
D. routine inquiry

Asked by tamra454

Answer (3)

5x-3y=6 2x-5y=10 Make a reduction. Multiply the first by 2, the second by 5: 10x-6y=12 10x-25y=50
-19y=38 y=-2 5x-3(-2)=6 5x+6=6 5x=0 x=0 The solution is (x;y)=(0;-2)

Answered by Anonymous | 2024-06-10

The solution to the system of equations 5x-3y=6 and 2x-5y=10 is x = 0 and y = -2.
To find the solution to the system of equations:
5x - 3y = 6 ...(1)
2x - 5y = 10....(2)
Use the elimination method to find the solution:
Multiply both sides of equation (1) by 2 to make the coefficients of 'x' in both equations equal:
2(5x - 3y) = 2(6)
10x - 6y = 12
Now, we have the following two equations :
10x - 6y = 12
2x - 5y = 10
Multiply both sides of equation (2) by 5 to make the coefficients of 'y' in both equations equal:
5(2x - 5y) = 5(10)
10x - 25y = 50
Now, we have the following two equations :
10x - 6y = 12...(3)
10x - 25y = 50...(4)
Subtract equation (3) from equation (4) to eliminate 'x':
(10x - 25y) - (10x - 6y) = 50 - 12
-19y = 38
Divide both sides by -19 to solve for 'y':
y = 38 / -19
y = -2
Now that we have the value of 'y', substitute it back into either equation (1) or (2) to find 'x'.
Use equation (1):
10x - 6(-2) = 12
10x + 12 = 12
Subtract 12 from both sides:
10x = 0
x = 0
So, the solution to the system of equations is x = 0 and y = -2.
To learn more on Equation :
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Answered by pukhrajvt | 2024-06-18

The solution to the system of equations 5 x − 3 y = 6 and 2 x − 5 y = 10 is ( x , y ) = ( 0 , − 2 ) . This was found by using the elimination method to isolate one variable and solve for both. The point (0, -2) is where the two lines intersect.
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Answered by Anonymous | 2024-10-02