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In Mathematics / College | 2025-07-07

Find the equation of the line with slope = [tex]$\frac{1}{3}$[/tex] and passing through the point (4,7).

Asked by savannahknight72

Answer (1)

Use the point-slope form of a line: y − y 1 ​ = m ( x − x 1 ​ ) .
Substitute the given slope m = 3 1 ​ and point ( 4 , 7 ) into the equation: y − 7 = 3 1 ​ ( x − 4 ) .
Simplify the equation to slope-intercept form: y = 3 1 ​ x − 3 4 ​ + 7 .
Combine constants to get the final equation: y = 3 1 ​ x + 3 17 ​ .

y = 3 1 ​ x + 3 17 ​ ​
Explanation

Understanding the Problem We are given the slope of a line, which is 3 1 ​ , and a point that the line passes through, which is ( 4 , 7 ) . Our goal is to find the equation of this line.

Using Point-Slope Form We will use the point-slope form of a linear equation, which is given by: y − y 1 ​ = m ( x − x 1 ​ ) where m is the slope of the line and ( x 1 ​ , y 1 ​ ) is a point on the line.

Substituting Values We are given that the slope m = 3 1 ​ and the point ( x 1 ​ , y 1 ​ ) = ( 4 , 7 ) . Substituting these values into the point-slope form, we get: y − 7 = 3 1 ​ ( x − 4 )

Distributing Now, we simplify the equation to get it into slope-intercept form, which is y = m x + b , where m is the slope and b is the y-intercept. First, distribute the 3 1 ​ on the right side: y − 7 = 3 1 ​ x − 3 4 ​

Isolating y Next, add 7 to both sides of the equation to isolate y :
y = 3 1 ​ x − 3 4 ​ + 7

Simplifying To combine the constants, we need a common denominator. Since 7 = 3 21 ​ , we have: y = 3 1 ​ x − 3 4 ​ + 3 21 ​ y = 3 1 ​ x + 3 17 ​

Final Answer So, the equation of the line in slope-intercept form is: y = 3 1 ​ x + 3 17 ​


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