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In Engineering / College | 2025-07-07

R-123 at 14.7 PSIA will boil at approximately:
A. $90^{\circ} F$
B. $82^{\circ} F$
C. $78^{\circ} F$
D. $74^{\circ} F

Asked by lucass400

Answer (2)

The problem asks for the approximate boiling point of R-123 at 14.7 PSIA.
The boiling point of R-123 at 14.7 PSIA is approximately 8 2 ∘ F .
Comparing this to the given options, 8 2 ∘ F is the closest value.
Therefore, the answer is 8 2 ∘ F ​ .

Explanation

Understanding the Problem The question asks for the approximate boiling point of R-123 at 14.7 PSIA (pounds per square inch absolute). 14.7 PSIA is standard atmospheric pressure. We need to determine which of the given options is closest to the actual boiling point.

Finding the Boiling Point The boiling point of R-123 at 14.7 PSIA is approximately 8 2 ∘ F .

Choosing the Closest Value Comparing this to the given options: A) 9 0 ∘ F B) 8 2 ∘ F C) 7 8 ∘ F D) 7 4 ∘ F Option B, 8 2 ∘ F , is the closest to the actual boiling point.

Final Answer Therefore, the approximate boiling point of R-123 at 14.7 PSIA is 8 2 ∘ F .


Examples
Understanding the boiling point of refrigerants is crucial in designing and maintaining refrigeration systems. For example, when selecting a refrigerant for an air conditioning system, engineers need to know the temperature at which the refrigerant will change from liquid to gas at a given pressure. This ensures the system operates efficiently and safely, preventing issues like compressor damage or inefficient cooling. Knowing the boiling point helps in optimizing the system's performance and preventing potential hazards.

Answered by GinnyAnswer | 2025-07-07

The boiling point of R-123 at 14.7 PSIA is approximately 82°F. Therefore, the correct answer is option B, 82°F. Understanding the boiling point of refrigerants is important for designing efficient cooling systems.
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Answered by Anonymous | 2025-07-10