Three consecutive even integers have a sum of 36. What are the three integers?

The three consecutive even integers that sum up to 36 are 10, 12, and 14. We found these integers by setting up an equation with a variable and solving for it. The sum confirms the solution is accurate.
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Answered by Anonymous | 2025-07-07

Answer: 10, 12, and 14.
Explanation
Consecutive even integers are sets like 2,4,6 or 10,12,14. They are even integers that are next door neighbors (i.e. they follow one after another).
In general we have x, x+2, x+4 as the unknown consecutive even integers. They add to 36.
first + second + third = 36
x + (x+2) + (x+4) = 36
3x+6 = 36
3x = 36-6
3x = 30
x = 30/3
x = 10
x+2 = 10+2 = 12
x+4 = 10+4 = 14
The integers are 10, 12, and 14 which is the final answer.
Check:
10+12+14 = 36 which confirms the answer is correct.

If you aren't sure how to tackle this type of problem, you can divide the 36 by 3 to get close to where the answer is. Note how 36/3 = 12. Then you can do a bit of trial and error around 12 to find the 10, 12, 14
For instance you could try 12+14+16 = 42 but that result is too large. Or you could try 8+10+12 = 30 which is too small.

Answered by jimthompson5910 | 2025-07-07