Our teacher divided 30 markers between two boys so that one boy got 4 more than the other. How many markers did each boy get?

Question

Anonymous · Answer

The first boy received 13 markers, while the second boy received 17 markers. This was determined by setting up an equation based on their total markers and the difference between them. The solution involved simple algebraic steps to find the number of markers each boy received. 
 ;

micaiahterry1 · Answer

Answer: 13 and 17 
 Step-by-step explanation: 2x+4 = 30. Subtract 4 on both sides, then you will get 2x=30-4. Simplify that and you'll get 2x = 26. Now divide both sides by two. Now you have the value for x. x = 13. Lastly, subtract that from 30 and you now you know how many markers each boy got

Our teacher divided 30 markers between two boys so that one boy got 4 more than the other. How many markers did each boy get?

Answer (2)

Related Questions in Mathematics

[Free] Select the correct answer. Which equation is equivalent to the given equation? [tex]$x^2-6 x=8$[/tex] A. [tex]$(x-6)^2=44$[/tex] B. [tex]$(x-3)^2=17$[/tex] C. [tex]$(x-6)^2=20$[/tex] D. [tex]$(x-3)^2=14$[/tex]

[Free] Which phrase best describes the translation from the graph [tex]y=6 x^2[/tex] to the graph of [tex]y=6(x+1)^2[/tex]? A. 6 units left B. 6 units right C. 1 unit left D. 1 unit right

[Free] What expression is equivalent to [tex]$\left(5 z^2+3 z+2\right)^2$[/tex] ? A. [tex]$5 z^4+3 z^2+4$[/tex] B. [tex]$5 z^4+9 z^2+4$[/tex] C. [tex]$25 z^4+30 z^3+19 z^2+12 z+4$[/tex] D. [tex]$25 z^4+30 z^3+29 z^2+12 z+4$[/tex]

[Free] The graph of [tex]y=\frac{5}{4} x+1[/tex] is shown below. The coordinate ([tex]0, y[/tex]) is a solution of the equation. Given the [tex]x[/tex]-value of 0, what is the value of the [tex]y[/tex]-coordinate for the coordinate ([tex]0, y[/tex])? [tex]y=[/tex] [blank]

[Free] If [tex]f(-2)=0[/tex], what are all the factors of the function [tex]f(x)=x^3-2 x^2-68 x-120[/tex]? Use the Remainder Theorem. A. [tex](x+2)(x+60)[/tex] B. [tex](x-2)(x-60)[/tex] C. [tex](x-10)(x+2)(x+6)[/tex] D. [tex](x+10)(x-2)(x-6)[/tex]