If the total resistance of two motor windings connected in parallel is 240 and 240V is applied to the circuit, how much current will flow?
Select one:
A. 10A
B. 12A
C. 14A
D. 20A
Answer (3)
The total current flowing through the circuit with two 240-ohm resistors in parallel and 240V applied is 2A. Therefore, none of the provided multiple-choice options are correct. It's important to verify the values and setup when calculating current using Ohm's Law.
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** A. 10A** ;
To determine the current flowing through the circuit, we can use Ohm's Law, which states that the current I flowing through a conductor between two points is directly proportional to the voltage V across the two points and inversely proportional to the resistance R of the conductor. The formula for Ohm's Law is:
I = R V
Given:
Total Resistance R = 240 Ω
Voltage V = 240 V
Substituting these values into the formula gives us:
I = 240 Ω 240 V = 1 A
This result suggests there might be a mistake in the understanding of what kind of parallel connection or calculation should be made because the direct calculation gives just 1 A . It's important to ensure that when motor windings or resistances are told to be connected in parallel, they should actually reduce the equivalent resistance, indicating that possibly this direct interpretation requires verifying true parallel configuration.
However, if the question is interpreted as having the combined effective resistance already calculated for the parallel system, then total current from the voltage will give:
For this question, if properly interpreted with the total resistance as intended for the entire parallel connection of windings, your correct result under Ohm's law was calculated to 1 A , yet an understanding may coordinate another situation resulting in other options.
Based on above calculation:
Selected answer A. 10A doesn't apply directly from a simple outcome as described, interpretation of parallel configuration of resistances must be clear for options matching.
