Q1. Add the following decimals.
(i) 0.4 + 0.3
(ii) 63.32 + 76.41
(iii) 27.25 + 62.23
(iv) 0.57 + 0.29
(v) 107.69 + 584.84
(vi) 2.1 + 1.7 + 0.8
(vii) 0.15 + 0.27
(viii) 0.24 + 0.36 + 0.75

Q2. Add the following after changing into like decimals.
(i) 36.795 + 26.45
(ii) 19.76 + 4.5 + 36.002
(iii) 0.005 + 9.4 + 30.66
(iv) 24.38 + 4.008 + 4.2
(v) 390.86 + 34.6 + 72
(vi) 26.12 + 70.596 + 13.7

Q3. A bag contains 45 kg 80 g sugar and the mass of the empty bag is 950 g. What is the mass of the bag containing this much sugar?

Let's solve each problem step by step.
Q1. Add the following decimals:
(i) 0.4 + 0.3 = 0.7
(ii) 63.32 + 76.41 = 139.73
(iii) 27.25 + 62.23 = 89.48
(iv) 0.57 + 0.29 = 0.86
(v) 107.69 + 584.84 = 692.53
(vi) 2.1 + 1.7 + 0.8 = 4.6
(vii) 0.15 + 0.27 = 0.42
(viii) 0.24 + 0.36 + 0.75 = 1.35
Q2. Add the following after changing into like decimals:
(i) 36.795 + 26.450 = 63.245
(ii) 19.760 + 4.500 + 36.002 = 60.262
(iii) 0.005 + 9.400 + 30.660 = 40.065
(iv) 24.380 + 4.008 + 4.200 = 32.588
(v) 390.860 + 34.600 + 72.000 = 497.460
(vi) 26.120 + 70.596 + 13.700 = 110.416
Q3. A bag contains 45 kg 80 g sugar and the mass of the empty bag is 950 g. What is the mass of the bag containing this much sugar?
First, convert the weight of the sugar entirely into grams:

45 kg is 45 × 1000 = 45000 grams.
Adding the 80 g , the total sugar weight is 45000 + 80 = 45080 grams.

Now, add this to the weight of the empty bag:

The mass of the empty bag is 950 g .
Therefore, the total mass of the bag with the sugar is 45080 + 950 = 46030 grams.

Thus, the mass of the bag containing the sugar is 46030 grams or 46.03 kilograms .

Answered by MasonWilliamTurner | 2025-07-06