5. The cost of a computer is ₹75750. Find the cost of 110 such computers.
6. There are 240 pages in a book. Find the total number of pages in such 3268 books.
Answer (1)
To solve these problems, we need to apply basic multiplication.
Cost of 110 computers :
The cost of one computer is ₹75,750. To find the cost of 110 computers, we'll multiply the cost of one computer by 110.
Total cost = 75 , 750 × 110
Let's perform the multiplication:
75 , 750 × 110 = 75 , 750 × ( 100 + 10 ) = 75 , 750 × 100 + 75 , 750 × 10
First, calculate the multiplication by 100 and 10 separately:
75 , 750 × 100 = 7 , 575 , 000
75 , 750 × 10 = 757 , 500
Now, add these two results:
7 , 575 , 000 + 757 , 500 = 8 , 332 , 500
Therefore, the total cost of 110 computers is ₹8,332,500.
Total number of pages in 3268 books :
Each book has 240 pages. To find the total number of pages in 3,268 books, multiply the number of pages in one book by 3,268.
Total pages = 240 × 3 , 268
Let's perform the multiplication:
Using the distributive property, break down 3,268 into smaller parts:
240 × 3 , 268 = 240 × ( 3 , 000 + 200 + 60 + 8 )
Calculate each part separately:
240 × 3 , 000 = 720 , 000
240 × 200 = 48 , 000
240 × 60 = 14 , 400
240 × 8 = 1 , 920
Now, sum up all these parts:
720 , 000 + 48 , 000 + 14 , 400 + 1 , 920 = 784 , 320
Therefore, the total number of pages in 3,268 books is 784,320 pages.
