A musician has 5 songs she can play at an open music night. How many different ways can she play 2 of them?

She can do it 10 different ways . 5 times 2

Answered by brittanycandace | 2024-06-10

The question is asking how many different ways a musician can play 2 songs out of 5 available songs. This type of problem is solved using the concept of combinations, as the order in which the songs are played does not matter.
To find the total number of combinations in which two songs can be selected from five, we use the combination formula, which is:
C(n, k) = n! / (k!(n-k)!)
Where: n = total number of items to choose from (in this case, 5 songs), k = number of items to choose (in this case, 2 songs).
Substituting the values we get:
C(5, 2) = 5! / (2!(5-2)!) C(5, 2) = 120 / (2*6) C(5, 2) = 120 / 12 C(5, 2) = 10
Therefore, the musician can play the songs in 10 different ways.

Answered by JoaquinRafael | 2024-06-24

The musician can play 2 out of 5 songs in 10 different ways. This is calculated using the combinations formula C(5, 2) = 10. Combinations are used here because the order of songs played does not matter.
;

Answered by JoaquinRafael | 2024-12-20