Find the equation of the line that is perpendicular to \(-5x + y = 5\) and passes through the point \((5,5)\). Express your answer in slope-intercept form.
Answer (2)
Before finding the perpendicular line, you need to know that perpendicular lines are negative reciprocal of each other. x to 1/(-x) so from the equation thats given: -5x+y=5 y=5x+5 set it to slope intercept form then you will find the slope from the equation which is 5 .
Since its perpendicular so the slope of the other line will be 1/-5 or -1/5 then use ****point slope formula to find the equation of the perpendicular line y-y1=m(x-x1) plug the given coordinate(5,5) y-(5)=-1/5(x-5) y-5=-1/5x+1 +5 +5 y=-1/5+6 will be your answer.!
The equation of the line that is perpendicular to − 5 x + y = 5 and passes through the point ( 5 , 5 ) is y = − 5 1 x + 6 . This was found by determining the slope of the original line, using the negative reciprocal to find the perpendicular slope, and applying the point-slope formula. The final answer is expressed in slope-intercept form.
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