The length of a rectangle is one more than five times its width. If the perimeter is 38, find the dimensions. Show your work.
Answer (3)
x − w i d t h 5 x + 1 − l e n g t h 2 x + 2 ( 5 x + 1 ) = 38 2 x + 10 x + 2 = 38 2 x + 10 x = 38 − 2 12 x = 36 ∣ : 12 x = 3 5 ⋅ 3 + 1 = 15 + 1 = 16 D im e n s i o n s : 3 an d 16
A **rectangle's **length is one greater than five times its breadth . if the perimeter is 38. This will have **dimensions **of 3 and 16.
What are the dimensions of a rectangle?
There are two **dimensions **to a rectangle: the length and the width , which are measured in relation to the length . Oval and triangular **interiors **have only two dimensions.
Since a **rectangle **is a two-dimensional form, it has two dimensions : length and width. The rectangle's length is its **longer **side, while its width is its **shorter **side.
**Area **only has two dimensions. **length **into width In some circumstances, we might state that **dividing **a length by a length **produces **the area of a square. The methods used to **collect **area vary depending on the shape .
A dimension , whether it be in terms of length , width, height, or something else, is a **solid **place to start when looking at a **figure's **other characteristics . The distance along the figure's outer edge is measured in terms of its perimeter .
Width = x
**Length **= 5x + 1
2x + 2(5x + 1) = 38
2x + 10x +2 = 38
12x = **38 **- 2
x = 36 / 12
x= 3
After this, **value **of x will be putted in 5x + 1.
Therefore, a **rectangle's **length is one greater than five times its breadth . if the perimeter is 38. This will have **dimensions **of 3 and 16.
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The width of the rectangle is 3 units, and the length is 16 units. This satisfies the conditions given in the problem about the length being one more than five times the width and the perimeter being 38. Thus, the dimensions are correctly calculated as 3 and 16.
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