When factored completely, what are the factors of \(4x^2 - 16\)?

U se : a 2 − b 2 = ( a − b ) ( a + b ) 4 x 2 − 16 = 4 ( x 2 − 4 ) = 4 ( x 2 − 2 2 ) = 4 ( x − 2 ) ( x + 2 ) ​

Answered by Anonymous | 2024-06-10

4 x 2 − 16 = 4 ( x 2 − 4 ) = 4 ( x − 2 ) ( x + 2 )

Answered by konrad509 | 2024-06-10

The expression 4 x 2 − 16 can be factored as 4 ( x − 2 ) ( x + 2 ) by recognizing it as a difference of squares. First, identify 4 x 2 as ( 2 x ) 2 and 16 as 4 2 , and then apply the difference of squares formula. Finally, factor out the greatest common factor to reach the complete factored form.
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Answered by Anonymous | 2025-01-08