Find the equation of the circle with center (0, 0) that contains the point (5, -2).

The general equation of a circle centered at (0, 0) is given by:
\[ x^2 + y^2 = r^2 \]

Calculate \( r^2 \) using the point (5, -2):
\[ r^2 = 5^2 + (-2)^2 \]

( 5 − 0 ) 2 + ( − 2 + 0 ) 2 = r 2 25 + 4 = r 2 29 = r 2 x 2 + y 2 = 29 ​ ​

Answered by konrad509 | 2024-06-10

The equation of the circle centered at (0, 0) that contains the point (5, -2) is x 2 + y 2 = 29 . This is derived by calculating the distance from the center to the point, resulting in a radius squared of 29.
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Answered by Anonymous | 2024-12-26