What are the coordinates of the turning point of the graph of \( y = 2x^2 - 4x + 1 \)?

x=-b/2a=-(-4)/2(2)=4/4=1 y=2(1)^2-4(1)+1=-1 so the point is (1,-1)

Answered by omomo | 2024-06-10

An **equation **is formed of two **equal expressions. **The **coordinates **of the **turning **point of the graph of y=2x²-4x+1 are (1,-1).
What is an equation?
An **equation **is formed when two **equal expressions **are equated together with the help of an equal sign '='.
The **turning **point of the graph is the **vertex **of the **parabolic graph. **Therefore, the **coordinates **of the **turning **point of the graph of y=2x²-4x+1 are (1,-1).

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Answered by ap8997154 | 2024-06-16

The turning point of the graph of y = 2 x 2 − 4 x + 1 is at the coordinates ( 1 , − 1 ) . This point is found by calculating the vertex of the parabola. The x-coordinate is obtained using x = − 2 a b ​ , resulting in x = 1 , and substituting back into the equation gives y = − 1 .
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Answered by ap8997154 | 2024-12-18