y = 11 ( 9 0 ) + 3 y = 11 ⋅ 1 + 3 y = 14
The y-intercept is ( 0 , 14 )
the y-intercept is when the y-coordinate is at 0 or when x=0 so set x to 0
y=11(9^x)+3 anything to the 0 power=1 so y=11(1)+3 y=11+3 y=14
The y-intercept of the equation y = 11 ( 9 x ) + 3 is found by substituting x = 0 , resulting in y = 14 . Therefore, the y-intercept is at the point ( 0 , 14 ) .
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