If \( P(-2, 1) \) is rotated 90°, its image is:

The image of P(-2,1) after it is rotated 90° is (-1,-2).

Answered by jayceirwin1 | 2024-06-10

Image = (-1, -2) ;

Answered by OrethaWilkison | 2024-06-24

The image of the point P(-2, 1) after a 90° counterclockwise rotation is P'(-1, -2). This is found by applying the rotation transformation rule, which swaps and negates the coordinates. Therefore, the final coordinates become P'(-1, -2).
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Answered by OrethaWilkison | 2024-09-10