A conveyor belt carries supplies from the first floor to the second floor, which is 15 ft higher. The belt makes a 60-degree angle with the ground.

1. How far do the supplies travel from one end of the conveyor belt to the other? Round to the nearest foot.

2. If the belt moves at 75 ft/min, how long, to the nearest tenth of a minute, does it take the supplies to move to the second floor?

A. 17 ft, 0.2 min
B. 21 ft, 12.8 min
C. 26 ft, 24 min
D. 9 ft, 0.9 min

Well this is a simple trig question, for this use the sine rule: Whatever you are looking for will be on the top so in this case length will be on the top. a/sinA = b/sinB, a = 15, b=b, A = 60 and B = 90 (Assumption) Re-arrange for b: b = a(sinB)/SinA = 15(sin60)/sin90 b = 13ft
v = s/t where v = velocity, s = distance and t = time taken we are looking for t so: t = s/v = 13/75 t = 0.173
So the time in minutes would be 0.173 x 60 = 10.4 minutes

Answered by jdpclarke | 2024-06-10

The supplies travel a distance of approximately 17 ft along the conveyor belt and take about 0.2 minutes to reach the second floor. Therefore, the correct answer is A. 17 ft, 0.2 min.
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Answered by jdpclarke | 2024-12-26