The sum of a number times 6 and 19 is at least -29.

The missing number is -16
6x + 19 = -29 Subtract 19 on both sides 6x = -29 - 19
6x = -48 Divide by 6 on both sides
x= -16

Answered by lindaineus | 2024-06-10

The mathematical equation to represent the statement 'the sum of a number times 6 and 19 is at least -29' is 6x + 19 ≥ -29. To solve this inequality, we follow these steps:
Subtract 19 from both sides of the inequality to isolate the term containing the variable: 6x ≥ -29 - 19.
Combine the constants on the right side: 6x ≥ -48.
Divide both sides by 6 to solve for x: x ≥ -8.
This means that any number greater than or equal to -8 will satisfy the inequality when multiplied by 6 and added to 19.

Answered by LevonHelm | 2024-06-24

The solution to the problem shows that the number x must be greater than or equal to -8, which is expressed as x ≥ − 8 . Any number in this range will satisfy the condition given in the question. Examples show that both x = − 8 and x = − 7 hold true for the inequality.
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Answered by lindaineus | 2024-09-30