How do I write a point-slope form equation that contains the points (3, -5) and (-5, 3)?

G e n er a l e q u a t i o n f or l in e in s l o p e in t erce pt f or m : y = a x + b T o f in d a an d b s u b s t i t u d e p o in t s ( 3 , − 5 ) , ( − 5 , 3 ) in t o e q u a t i o n { 3 = − 5 a + b ∣ ∗ − 1 − 5 = 3 a + b ​ { − 3 = 5 a − b − 5 = 3 a + b ​ + − − − − − 8 = 8 a ∣ : 8 a = − 1 − 5 = 3 ⋅ ( − 1 ) + b − 5 = − 3 + b − 5 + 3 = b b = − 2 y = − x − 2

Answered by luana | 2024-06-10

Steps:

First you have to find the slope 3+5= 8 -5-3=-8 Your slope is -1
You plug in one of the points into the point slope form Y1-Y2=m(x-x1) Y-3=-1(x+5) Y-3=-1x+-5
Then, you add three to each side Y=-1x+ (-2)

Answered by Porshia | 2024-06-10

To find the point-slope form equation through the points (3, -5) and (-5, 3), first calculate the slope as -1 using the formula m = x 2 ​ − x 1 ​ y 2 ​ − y 1 ​ ​ . Then use the point-slope equation y − y 1 ​ = m ( x − x 1 ​ ) with one of the points to write the line equation.
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Answered by luana | 2024-12-26