JY CHEN - Ask Anything, Learn Everything. Logo

In Mathematics / High School | 2014-11-24

What is the value of \( m \) in the equation \(\frac{1}{2}m - \frac{3}{4}n = 16\) when \( n = 8 \)?

Asked by jcharris503

Answer (2)

2 1 ​ m − 4 3 ​ n = 16 n = 8 2 1 ​ m − 4 3 ​ ⋅ 8 = 16 2 1 ​ m − 6 = 16 2 1 ​ m = 16 + 6 2 1 ​ m = 22 ∣ ⋅ 2 m = 44

Answered by luana | 2024-06-10

To find m , we substitute n = 8 into the equation 2 1 ​ m − 4 3 ​ n = 16 . After simplifying, we find that the value of m is 44.
;

Answered by luana | 2024-12-23

Related Questions in Mathematics

[Free] Select the correct answer. Which equation is equivalent to the given equation? [tex]$x^2-6 x=8$[/tex] A. [tex]$(x-6)^2=44$[/tex] B. [tex]$(x-3)^2=17$[/tex] C. [tex]$(x-6)^2=20$[/tex] D. [tex]$(x-3)^2=14$[/tex]

[Free] Which phrase best describes the translation from the graph [tex]y=6 x^2[/tex] to the graph of [tex]y=6(x+1)^2[/tex]? A. 6 units left B. 6 units right C. 1 unit left D. 1 unit right

[Free] What expression is equivalent to [tex]$\left(5 z^2+3 z+2\right)^2$[/tex] ? A. [tex]$5 z^4+3 z^2+4$[/tex] B. [tex]$5 z^4+9 z^2+4$[/tex] C. [tex]$25 z^4+30 z^3+19 z^2+12 z+4$[/tex] D. [tex]$25 z^4+30 z^3+29 z^2+12 z+4$[/tex]

[Free] The graph of [tex]y=\frac{5}{4} x+1[/tex] is shown below. The coordinate ([tex]0, y[/tex]) is a solution of the equation. Given the [tex]x[/tex]-value of 0, what is the value of the [tex]y[/tex]-coordinate for the coordinate ([tex]0, y[/tex])? [tex]y=[/tex] [blank]

[Free] If [tex]f(-2)=0[/tex], what are all the factors of the function [tex]f(x)=x^3-2 x^2-68 x-120[/tex]? Use the Remainder Theorem. A. [tex](x+2)(x+60)[/tex] B. [tex](x-2)(x-60)[/tex] C. [tex](x-10)(x+2)(x+6)[/tex] D. [tex](x+10)(x-2)(x-6)[/tex]