so monkeys/3=lions or monkeys=3(lions) monkeys+lions=24 subsitute monkeys=3(lions) for monkeys in the second equation 3(lions)+lions=24 add like terms 4lions=24 divide both sides by 4 lions=6 subsitute lions=6 into second equation monkeys+6=24 subtract 6 from both sides monkeys=18
3 x − m o nk eys x − l i o n s 3 x + x = 24 4 x = 24 d i v i d e b y 4 x = 6 3 x = 18 T h ere a re 18 m o nk eys an d 6 l i o n s .
The problem shows that there are 18 monkeys and 6 lions at the zoo. We found this by letting the number of lions be L and the monkeys M = 3 L and setting up the equation M + L = 24 . Solving these equations gives us the final counts of each animal.
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