Two welders working together can complete a job in 6 hours. One of the welders, working alone, can complete the task in 15 hours. How long would it take the second welder, working alone, to complete the task?
Answer (2)
ur asking a bunch of these kind of rate problems xD 6 ( 15 1 + x 1 ) = 1 In 6 hrs, the welder who does 1/15 of the job in 1 hr and the welder who does 1/x in 1 hr, complete the job (6 hrs.) 15 1 + x 1 = 6 1 Multiply 30 on both sides to cancel out the fractions and we get: 2 + x 30 = 5 Solving for x: 30/x=3 3x=30 x=10 The second welder would take 10 hours.
The second welder can complete the task alone in 10 hours. This is determined by calculating the work rates of both welders and combining them accordingly. By solving the equation formed by their work rates, we find the individual time for the second welder.
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