Factor completely:

\[ x^4 + 8x^2 - 9 \]

x 4 + 8 x 2 − 9 = x 4 − x 2 + 9 x 2 − 9 = x 2 ( x 2 − 1 ) + 9 ( x 2 − 1 ) = ( x 2 + 9 ) ( x 2 − 1 ) = ( x 2 + 9 ) ( x − 1 ) ( x + 1 )

Answered by konrad509 | 2024-06-10

To factor the polynomial x 4 + 8 x 2 − 9 , we substitute y = x 2 and factor the resulting quadratic. This leads to the expression ( x 2 + 9 ) ( x + 1 ) ( x − 1 ) . The complete factorization is thus ( x 2 + 9 ) ( x + 1 ) ( x − 1 ) .
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Answered by Anonymous | 2024-10-09