The length of a rectangular field is 4 meters longer than its width. If the perimeter is 56 meters, what is the width of the field?

We know the perimeter is the sum of all sides. So lenght+length+width+width = 2length+2width. Let's call the width x. If the length is 4m longer, then it's x+4. We know the perimeter, so we can make an equation: 56=2x+2(x+4) And solve from there: 56=2x+2x+8 56=4x+8 48=4x 48/4=x x=12
The width, which is x, is 12 m. And the length, x+4, is 16 m. You can check this is correct by calculating the perimeter using those values: 12+12+16+16=56.

Answered by ljndr | 2024-06-10

To find the width of a rectangular field with a perimeter of 56 meters where the length is 4 meters longer than the width, we set up the equation 2(w + 4) + 2w = 56, simplify it to 4w + 8 = 56, subtract 8 to get 4w = 48, and divide by 4 to find that the width is 12 meters. ;

Answered by siddharth8299jai | 2024-06-24

The width of the rectangular field is 12 meters, found by setting up the perimeter equation. By defining width as w and length as w + 4 , we solved the resulting equation. Thus, the dimensions align with the given perimeter of 56 meters.
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Answered by siddharth8299jai | 2024-12-18