A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry, so the coach bought 6 more hamburgers and 2 more fries for $16.60. Find the cost of each hamburger and each fry.
Let:
\[ h = \text{cost of one hamburger} \]
\[ f = \text{cost of one fry} \]
Formulate the system of equations:
\[ 8h + 5f = 24 \]
\[ 6h + 2f = 16.60 \]
Solve the system of equations to find the values of \( h \) and \( f \).
Answer (3)
Answer : The cost of hamburgers and fries is, $2.5 and $0.8
Step-by-step explanation :
Let the cost of hamburgers be, x and the cost of fries be, y.
Thus the two equation will be:
8 x + 5 y = 24 ...........(1)
6 x + 2 y = 16.60 .............(2)
Using substitution method:
From equation 1 we have to determine the value of 'y'.
8 x + 5 y = 24
5 y = 24 − 8 x
y = 5 24 − 8 x ........(3)
Now put equation 3 in 2, we get:
6 x + 2 y = 16.60
6 x + 2 × ( 5 24 − 8 x ) = 16.60
6 x + ( 5 48 − 16 x ) = 16.60
5 30 x + 48 − 16 x = 16.60
30 x + 48 − 16 x = 83
14 x = 35
x = 2.5
Now put the value of x in equation 3, we get:
y = 5 24 − 8 x
y = 5 24 − 8 × 2.5
y = 5 24 − 20
y = 5 4
y = 0.8
Thus, the cost of hamburgers and fries is, $2.5 and $0.8
Basically this is a systems of equations question. We set up two equations, X is hamburgers Y is fries
8x + 5y = 24 6x + 2y = 16.60
then you solve for each to get your answer.
The cost of one hamburger is $2.50 and the cost of one fry is $0.80. We found these values by setting up a system of equations based on the given purchases and solving them step-by-step. By simplifying and substituting values, we obtained the costs of each item.
;
