a 2 − 8 a + 15 = 0 a 2 − 8 a + 16 − 1 = 0 ( a − 4 ) 2 = 1 a − 4 = 1 ∨ a − 4 = − 1 a = 5 ∨ a = 3
To complete the square for a 2 − 8 a + 15 = 0 , first move the constant to the other side and then add and subtract the square of half the coefficient of a . This leads to the perfect square ( a − 4 ) 2 = 1 , which gives solutions a = 5 and a = 3 .
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