Help me, please!! Estoy desesperada y no hablo inglês!! Help

Log x^n = nLog x log x + log x^2 + log x^3 Log x + 2 log x +3 log x = -6 6 log x = -6 Log x = -1 X=10^-1 = 1/10 Respuesta final X=1/10

Answered by FirstSineOfMadness | 2024-06-10

0\\ \log x+\log x^2+\log x^3=-6\\ \log (x\cdot x^2\cdot x^3)=\log 10^{-6}\\ x^6=10^{-6}\\ x^6=\left(\frac{1}{10}\right)^6\\ \boxed{x=\frac{1}{10}}"> D : x > 0 lo g x + lo g x 2 + lo g x 3 = − 6 lo g ( x ⋅ x 2 ⋅ x 3 ) = lo g 1 0 − 6 x 6 = 1 0 − 6 x 6 = ( 10 1 ​ ) 6 x = 10 1 ​ ​

Answered by konrad509 | 2024-06-10

To solve the logarithmic equation log(x) + log(x^2) + log(x^3) = -6, you can combine the log terms to get log(x^6) = -6. By exponentiating both sides, you find x = 10^{-1}, which simplifies to x = 1/10. Therefore, the final answer is x = 1/10.
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Answered by FirstSineOfMadness | 2024-12-26