The sum of three consecutive odd numbers is 75. What is the smallest of these numbers, \( n \)?

Let x equal the lowest of the 3 consecutive odd integers: (x) + (x + 2) + (x + 4) = 75 Combine like terms: 3x + 6 = 75 -6 -6 3x = 69 /3 /3 x = 23 The lowest integer is 23. The 3 integers, therefore, are 23, 25, and 27. Hope this helps!
~ArchimedesEleven

Answered by ArchimedesEleven | 2024-06-10

a , a + 2 , a + 4 − t h ree o dd n u mb ers a + a + 2 + a + 4 = 75 3 a + 6 = 75 ∣ s u b t r a c t 6 3 a = 69 ∣ d i v i d e b y 3 a = 23 T h e s ma ll es t n u mb er i s 23.

Answered by luana | 2024-06-10

The smallest of the three consecutive odd numbers that sum to 75 is 23. The three numbers are 23, 25, and 27. This can be verified by checking their sum, which equals 75.
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Answered by ArchimedesEleven | 2025-02-02