Solve the system of equations:

1. \(3x + y + z = 4\)

2. \(2x + 2y + 3z = 3\)

3. \(x + 3y + 2z = 5\)

1) 3x+y+z=4 2) 2x+2y+3z=3 3) x+3y+2z = 5
1)*2 6x + 2y + 2z = 8 2) 2x + 2y +3z = 3

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4x - z = 5

2)*3 6x + 6y + 9z = 9 3)*2 2x + 6y + 4z = 10

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4x+5z =-1
4x+5z = -1
4x - z =5
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6z = -6 z = -1 If z=-1,
4x -(-1) =5 4x = 5-1 x = 4/4 x=1
3x+y+z=4 3(1)+y+(-1)=4 3+y-1=4 ** y=2
So z=-1, x=1, y=2 **

Answered by ollieboyne | 2024-06-10

The solution to the system of equations is x = 1 , y = 2 , and z = − 1 . This was achieved by eliminating one variable and solving the resulting equations step by step. The solution can be verified by substituting back into the original equations.
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Answered by ollieboyne | 2024-12-26