The length of a rectangle is 5 meters more than its width. The perimeter is 66 meters. Find the dimensions of the rectangle.

the length is 19 meters by a width of 14 meters.

Answered by themaninthepainting | 2024-06-10

To find the dimensions of a rectangle with a perimeter of 66 meters, where the length is 5 meters more than the width, we set up the equation 66 = 2(w + 5) + 2w. Solving for w gives us a width of 14 meters, and thus the length is 19 meters.

The student is asking to find the dimensions of a rectangle given that its length is 5 meters more than its width and that the rectangle's perimeter is 66 meters. To solve this problem, let's use the formula for perimeter which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width. We can create and solve an equation to find the width and then the length.
First, let's let w represent the width of the rectangle, then the length will be w+5. Now we can write the equation based on the perimeter:
66 = 2(w + 5) + 2w
66 = 2w + 10 + 2w
66 = 4w + 10
56 = 4w
14 = w
So, the width of the rectangle is 14 meters. Now let's find the length:
Length = w + 5 = 14 + 5 = 19 meters.
Therefore, the dimensions of the rectangle are a width of 14 meters and a length of 19 meters.

Answered by SachinM | 2024-06-24

The dimensions of the rectangle are 14 meters in width and 19 meters in length. The width was defined as w , and the length was found by adding 5 meters to the width. Using the perimeter formula, we solved for the width and then for the length.
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Answered by themaninthepainting | 2024-10-09