A 3-kilogram ball is accelerated from rest to a speed of 10 m/s. What is the ball's change in momentum?

Change in Momentum = mv - mu.
u = 0, v = 10 m/s. Note ball accelerated from rest, so initial velocity = 0. u =0
Change in Momentum = mv - mu = 3 10 - 3 0 =30.
Change in Momentum = 30 kgm/s.

Answered by olemakpadu | 2024-06-10

Formula for change in momentum is given by .
Δ P = m v − m u
Where m is mass , v is final velocity and u is initial velocity .
As given
A 3-kilogram ball is accelerated from rest to a speed of 10 m/sec.
m = 3
u = 0 m/sec
v = 10 m/sec
Putting values in the formula
Δ P = 3 × 10 − 3 × 0
Δ P = 30 k g m / sec
Therefore the change in momentum of ball is 30kg m/sec .

Answered by JackelineCasarez | 2024-06-11

The change in momentum of the tennis ball after striking the wall is − 1.044 kg m/s . This value reflects both a change in speed and direction. The initial momentum was 0.58 kg m/s and after rebounding it becomes − 0.464 kg m/s .
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Answered by JackelineCasarez | 2024-10-30