How do you solve the following system of equations?

1. \( x - y = 3 \)
2. \( 6x + 4y = 13 \)

x - y = 3 6x + 4y = 13
x = y + 3
6(y + 3) + 4y = 13 6y + 18 + 4y = 13 10y = 13 - 18 10y = - 5 y = - 5/10 y = - 1/2
x = - 1/2 + 3 x = - 1/2 + 6/2 x = 5/2

Answered by eah | 2024-06-10

{ 6 x + 4 y = 13 x − y = 3 ∣ ⋅ 4 ​ { 6 x + 4 y = 13 4 x − 4 y = 12 ​ + − − − − − 10 x = 25 ∣ : 10 x = 2.5 2.5 − y = 3 2.5 − 3 = y y = − 0.5 { x = 2.5 y = − 0.5 ​

Answered by luana | 2024-06-10

To solve the system of equations, we first isolate x in the first equation and then substitute it into the second equation. This gives us a value for y, which we then substitute back to find x. The final solution is x = 2 5 ​ and y = − 2 1 ​ .
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Answered by eah | 2024-12-26