The bulletin board is 6 feet wide and 4 feet tall. The border is 3 inches wide. What are the dimensions inside the border?

Because the boarder goes around all edges, 6 in must be subtracted from 6ft and 4ft. 6ft - 6in = 5.5 ft 4ft - 6in = 3.5 ft Area of the bulletin board: (5.5)(3.5) = 19.25 ft

Answered by kiersten979 | 2024-06-10

The dimensions are 5.5 feet by 3.5 feet.
The question asks for the dimensions inside the border of a bulletin board measuring 6 feet wide and 4 feet tall, with a border that is 3 inches wide.
To solve this, we need to subtract the width of the border from all sides of the bulletin board. Since there is a border on each side, we subtract twice the border's width from each dimension of the bulletin board.
Convert the border's width into feet: 3 inches is 1/4 foot (since 12 inches = 1 foot).
Subtract twice the border's width from the width of the board: 6 feet - 2*(1/4 foot) = 6 feet - 1/2 foot = 5.5 feet.
Subtract twice the border's width from the height of the board: 4 feet - 2*(1/4 foot) = 4 feet - 1/2 foot = 3.5 feet.
The dimensions inside the border are 5.5 feet wide and 3.5 feet tall.

Answered by AliciaAugello | 2024-06-25

The dimensions inside the border of the bulletin board are 5.5 feet wide and 3.5 feet tall. This is calculated by subtracting twice the width of the 3-inch border from the original dimensions of the board. After converting the border width to feet, we arrived at the final measurements.
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Answered by AliciaAugello | 2024-12-26