d c + 2 = g f ∣ s u b t r a c t 2 d c = g f − 2 ∣ m u lt i pl y b y d c = g fd − 2 d
To solve for c in the equation d + 2 c = g f , first cross-multiply to obtain c ⋅ g = f ⋅ ( d + 2 ) and then isolate c as c = g f ⋅ d + 2 f .
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