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In Mathematics / High School | 2014-10-26

The admission fee at a small fair is $1.50 for children and $4.00 for adults. On a certain day, 2,200 people entered the fair, and $5,050 was collected. How many children and how many adults attended?

(Note: A detailed explanation would be appreciated to understand the solution.)

Asked by crazymonkeymila

Answer (2)

x − c hi l d re n y − a d u lt s { 1 , 5 x + 4 y = 5050 x + y = 2200 ​ x = 2200 − y S u b s t i t u t i o n : 1 , 5 ( 2200 − y ) + 4 y = 5050 3300 − 1 , 5 y + 4 y = 5050 ∣ s u b t r a c t 3300 2 , 5 y = 1750 ∣ d i v i d e b y 2 , 5 y = 700 T h ere w ere 700 a d u lt s an d 1500 c hi l d re n .

Answered by luana | 2024-06-10

In total, 1500 children and 700 adults attended the fair. This was determined by setting up and solving a system of equations based on the total attendance and total fees collected. The equations utilized the admission fees to establish a relationship between the number of children and adults present at the fair.
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Answered by luana | 2024-12-26