x − b o tll e A y − b o ttl e B { 6 , 5 x + 8 , 25 y = 588 x + y = 84 { 6 , 5 x + 8 , 25 y = 588 x = 84 − y S u b s t i t u t i o n m e t h o d 6 , 5 ( 84 − y ) + 8 , 25 y = 588 546 − 6 , 5 y + 8 , 25 y = 588 ∣ s u b t r a c t 5461 , 75 y = 42 ∥ d i v i d e b y 1 , 75 y = 24 T h ere w ere 24 b o ttl es B an d 42 b o ttl e A .
The shipment consists of 60 bottles of type A conditioner and 24 bottles of type B conditioner. This was determined by solving a system of equations based on the total number of bottles and their combined cost. The algebraic approach used substitution to find the values of each type of bottle.
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