Let's call the height of the tallest pyramid x:
The base length is 3/2 * x (following the ratio) = 3x/2
This makes the volume, which follows the general formula V = 1/3 * base area * height = 1/3 * (3x/2)^2 * x = 1/3 * (9x^2)/4 * x = (3x^3)/4
The height of the smaller pyramids is x/2
The base length of these will be 3/2 * x/2 = 3x/4
This makes the volume, which also follows the formula above, 1/3 * (3x/4)^2 * x/2 = 1/3 * (9x^2)/16 * x/2 = (3x^3)/32
There are three smaller pyramids and one larger one, so the total volume is:
(3x^3)/4 + 3(3x^3)/32 = 30,000,000
This can be simplified by getting both algebraic fractions over the same denominator (namely getting the first over 32 instead of 4, by multiplying it by 8):
8(3x^3)/32 + 3(3x^3)/32 = 30,000,000 11(3x^3)/32 = 30,000,000 11(3x^3 ) = 30,000,000 * 32 = 960,000,000 33x^3 = 960,000,000 x^3 = 960,000,000 / 33 = 29090909.0909 x = cubic root of 29090909.0909 = 307.5523839ft
Now you just need to work out the dimensions and volumes of each pyramid:
LARGE Height = x = 307.5523839ft = 3.075523839 * 10^2 ≈ 3.076 * 10^2 ft Base length = 3x/2 = (3 * 307.5523839)/2 = 461.3285759 ≈ 4.613 * 10^2 ft Volume = (3x^3)/4 = (3 * 307.5523839^3)/4 = 21818181.81 ≈ 2.182 * 10^7 ft^3
SMALL Height = x/2 = 307.5523839/2 = 153.776192 ≈ 1.538 * 10^2 ft Base length = 3x/4 = (3 * 307.5523839)/4 = 230.6642879 ≈ 2.307 * 10^2 ft Volume = (3x^3)/32 = (3 * 307.5523839^3)/32 = 2727272.726 ≈ 2.727 * 10^6 ft^3
CHECK (2.182 * `10^7) + 3(2.727 * 10^6) = 30,001,000 ≈ 30,000,000 ft^3 (rounding error)
I hope this helps
The tallest pyramid has a height of approximately 308 feet and a base length of about 461 feet, with a volume of approximately 2.182 x 10^7 cubic feet. Each smaller pyramid has a height of around 154 feet, a base length of about 231 feet, and a volume of approximately 2.727 x 10^6 cubic feet. Together, these dimensions fit within the allocated stone volume of 30 million cubic feet.
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