3 x + 1 = 2 y − 5 y − 5 = 3 2 ( x + 1 ) y = 3 2 ( x + 1 ) + 5
To solve 3 x + 1 = 2 y − 5 for y , first cross-multiply, then distribute and isolate the y variable. The final equation can be represented as y = 3 2 ( x + 1 ) + 5 . This expresses y in terms of x .
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