Factor completely:

\[2x^3 + 22x^2 + 36x\]

2 x 3 + 22 x 2 + 36 x → 2 x ( x 2 + 11 x + 18 ) ​ 2 x ( x 2 + 9 x + 2 x + 18 ) = = 2 x [ x ( x + 9 ) + 2 ( x + 9 )] = = 2 x ( x + 9 ) ( x + 2 ) ​ ​

Answered by mariamikayla | 2024-06-10

2 x 3 + 22 x 2 + 36 x = 2 x ( x 2 + 11 x + 18 ) = 2 x ( x 2 + 9 x + 2 x + 18 ) = 2 x ( x ( x + 9 ) + 2 ( x + 9 )) = 2 x ( x + 2 ) ( x + 9 )

Answered by konrad509 | 2024-06-10

To factor 2 x 3 + 22 x 2 + 36 x completely, first factor out 2 x . This leads to 2 x ( x 2 + 11 x + 18 ) , which can further be factored into 2 x ( x + 2 ) ( x + 9 ) .
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Answered by mariamikayla | 2024-11-14